-y^2+250y-15000=0

Solution for -y^2+250y-15000=0 equation:

-y^2+250y-15000=0

We add all the numbers together, and all the variables

-1y^2+250y-15000=0

a = -1; b = 250; c = -15000;
Δ = b2-4ac
Δ = 2502-4·(-1)·(-15000)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(250)-50}{2*-1}=\frac{-300}{-2}
=+150
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(250)+50}{2*-1}=\frac{-200}{-2}
=+100
$